The average speed of a train is 20% less on the return journey than on the onward journey. The train halts for half an hour at the destination station before starting on the return journey. If the total time taken for the 'to and fro' journey is 23h covering a distance of 1000 km the speed of the train on the return journey is

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Solution

Train was halted for half an hour.
So, total time taken in Journey = 23 - (1/2) = 22.5 hours.
Average speed in Whole Journey = 1000/22.5 = 44.5 km/hr.
The average speed on return journey is 20% less than onward journey.
Therefore, ratio of average speed of onward and return journey,
= 100/80 = 5/4.
Let average speed of onward journey = 5x.
Average speed on return journey = 4x.
Average speed on whole journey = (5x +4x)/2
44.5 = (5x + 4x)/2
89 = 9x
x = 9.88.
Average speed on return = 9.88 *4 = 39.52 = 40 kmph (Approx.)

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