Question

The average speed of gas molecules in a gas present in equilibrium mixture is:

• A. $\propto T$
• B. $\propto T^2$
• C. $\propto \sqrt{T}$
• D. zero

Answer 1

Answer: (C)

$\propto \sqrt{T}$

As we know, the average speed of a gas molecule is given by,

$u_{av}=\sqrt{\frac{8RT}{\pi M}}$
So, for mixture $u_{av}\propto \sqrt{T}$

Hence, option $C$ is correct.