The average speed of molecules of a gas of molecular weight $M$ at temperature $T$ is :

0

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\sqrt{\frac{3 R T}{M}}

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\sqrt{\frac{8 R T}{π M}}

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\sqrt{\frac{2 R T}{M}}

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Solution

The correct option is C $\sqrt{\frac{8 R T}{π M}}$
Average velocity $v_{a v g} = \sqrt{\frac{8 k T}{m π}} = \sqrt{\frac{8 R T}{N_{a} m π}} = \sqrt{\frac{8 R T}{π M}}$

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M

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v_{1} = \sqrt{\frac{x_{1} R T}{M}}

v_{2} = \sqrt{\frac{x_{2} R T}{M}}

v_{3} = \sqrt{\frac{x_{3} R T}{M}}

v_{4} = \sqrt{\frac{x_{4} R T}{M}}

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