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Question

The average temperature of the town in the first four days of a month was 58 degrees. The average for the second, third, fourth and fifth day was 60 degrees. If the temperatures of the first and fifth day were in the ratio 7:8. Then what is the temperature on the fifth day?

A
64 degrees
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B
62 degrees
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C
56 degrees
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D
None of these
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Solution

The correct option is A 64 degrees
Let the temperatures on five days be x1,x2,x3,x4,x5

Given that the average temperature of the first four days is 58 degrees.

Therefore, 58=x1+x2+x3+x44

x1+x2+x3+x4=58×4=232

x2+x3+x4=232x1 ------(1)

Given that average for the second, third, fourth and fifth days is 60 degrees.

Therefore, 60=x2+x3+x4+x54

x2+x3+x4+x5=60×4=240 ------(2)

substituting (1) in (2) we get

232x1+x5=240

x5x1=8 -------(3)

Given that ratio of first-day and the fifth-day temperature is 7:8

Therefore, x1:x5=7:8

x1=78x5 ------(4)

substituting (4) in (3) we get

x578x5=8

878x5=8

x5=64

Therefore, the temperature on the fifth day is 64 degrees.

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