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Question

The average thermal energy for a diatomic gas molecule is (kB is Boltzmann constant, T is absolute temperature)

A
32kBT
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B
2kBT
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C
52kBT
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D
kBT
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Solution

The correct option is C 52kBT
Diatomic molecule has 3 translational degrees of freedom. In addition it has 2 rotational degrees of freedom.
Average thermal energy per degree of freedom
=12kBT
Total average thermal energy
= degree of freedom ×12kBT
=5×12kBT
=52kBT


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