Question

The average total energy in one time period of a particle of mass $m$ executing SHM of amplitude $a$ and angular velocity $\omega$ is

• A. $\frac{1}{2}m{\omega }^2{a}^2$
• B. $\frac{1}{4}m{\omega }^2{a}^2$
• C. $0$
• D. $m{\omega }^2{a}^2$
• E. $\frac{1}{8}m{\omega }^2{a}^2$

Answer 1

The correct option is A $\frac{1}{2}m{\omega }^2{a}^2$

The average total energy
$E=\frac{1}{2}m{\omega }^2{a}^2$
Total energy is not a position function.