Question

The average translational kinetic energy of air molecules is 0.040 eV (1 eV = 1.6 $\times {10}^{-19}$ J). Calculate the temperature of the air. Boltzmann constant k = 1.38 $\times 10-23J{K}^{-1}$

Answer 1

Average K.E = $\frac{3}{2}$

$\frac{3}{2}KT=0.04\times 1.6\times {10}^{-19}$

$\Rightarrow \frac{3}{2}\times 1.38\times {10}^{-23}\times T$

= $0.04\times 1.6\times {10}^{-19}$

$\Rightarrow T=\frac{2\times 0.004\times 1.6\times {10}^{-19}}{3\times 1.38\times {10}^{-23}}$

= $0.0309178\times {10}^4$

= 309.178 = 310 K