The average value of the wave-form shown in the figure above is

15 \sqrt{2}

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10 \sqrt{2}

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10

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15

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Solution

The correct option is D $15$
Area $0 A B E T$ = Area $0 A E T$ + Area $A B E$
= $10 T$ + $\frac{1}{2} 10 T$
= $15 T$
average value = $\frac{1}{T}$ Area $0 A B E T = 15 u n i t s$

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Similar questions

The value of $15 \sum r = 0^{15} C_{r} {(r - \frac{15}{2})}^{2}$ is

(15 \times 2 + 6) + 10

\frac{4}{15} {kg m}^{- 1}

(in m)

5 Hz

g = 10 {m/s}^{2}

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