The average velocity of a body moving with uniform acceleration travelling a distance 3.06m is 0.34m/s. If the change in velocity of the body is 0.18m/s during this time, its uniform acceleration is
A
0.01m/s2
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B
0.02m/s2
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C
0.03m/s2
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D
0.04m/s2
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Solution
The correct option is B0.02m/s2 Given, vavg=0.34m/s Change in velocity =0.18m/s Total time taken=DistanceAverage Velocity=3.060.34=9sec And, acceleration=change in velocitytime=0.189=0.02m/s2