The average velocity of a body of mass 10 kg is 20 m/s. If initial velocity of body is taken 10 m/s, find the change in momentum of body after it reaches the final velocity.?

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Solution

Dear Student
$A v e r a g e V e l o c i t y = \frac{I n i t i a l V e l o c i t y + F i n a l V e l o c i t y}{2} A v e r a g e V e l o c i t y = \frac{u + v}{2} 20 = \frac{10 + v}{2} 10 + v = 40 v = 30 m / s N o w i n i t a l M o m e n t u m p_{i} = m u = 10 \times 10 = 100 k g . m / s F i n a l M o m e n t u m, p_{f} = m v = 10 \times 30 = 300 k g . m / s C h a n g e i n m o m e n t u m = p_{f} - p_{i} = 300 - 100 = 200 k g . m / s$
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The average velocity of a body of mass 10 kg is 20 m/s. If initial velocity of body is taken 10 m/s, find the change in momentum of body after it reaches the final velocity.?

Dear Student Average Velocity =Initial Velocity + Final Velocity2Average Velocity =u + v220=10 + v210 +v = 40v = 30 m/sNow inital Momentum pi = mu = 10×10 = 100 kg .m/sFinal Momentum, pf = mv = 10×30 = 300 kg. m/sChange in momentum =pf-pi =300 -100 = 200 kg.m/s Regards