The average velocity of a particle performing S.H.M. in one oscillation is ----

\frac{4}{π}

times maximum velocity

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1}{π}

times maximum velocity

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{2}{π}

times maximum velocity.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 0
In one oscillation, displacement is zero, so the average velocity of particle in one oscillation is zero.
$v = \frac{d i s p l a c e m e n t}{t i m e i n t e r v a l} = \frac{0}{T} = 0 m / s$

Suggest Corrections

Similar questions

If a particle under S.H.M. has time period 0.1 sec and amplitude 2x $10^{- 3}$ m. It has maximum velocity

[RPET 2000]

25 c m / s

100 c m / s^{2}

(π = 3.142)

x = x_{0} s i n 2 π (n t - \frac{π}{λ})

0.16 m / s

0.64 m / s^{2}

y = y_{0} s i n 2 π

f t - \frac{π}{λ}

Join BYJU'S Learning Program