Question

The average velocity of an ideal gas molecule at ${27}^{0}C$ is 0.5 m/s, the average velocity at at ${927}^{0}C$ will be:

• A. 1 m/s
• B. 0.3 m/s
• C. 1.5 m/s
• D. 2 m/s

Answer 1

The correct option is A 1 m/s

$\frac{V_1}{V_2}=\frac{\sqrt{T_1}}{\sqrt{T_2}}$

$\frac{0.5}{V_2}=\frac{\sqrt{300}}{\sqrt{1200}}$

$V_2=1m/s$

Option $A$ is correct.