Question

The average velocity of an ideal gas molecule at ${27}^{\circ }C$ is 0.3 m/s. The average velocity at ${927}^{\circ }C$ will be:

• A. 0.6 m/s
• B. 0.3 m/s
• C. 0.9 m/s
• D. 3.0 m/s

Answer 1

The correct option is A 0.6 m/s

$V_{avg}=\sqrt{\frac{8RT}{\pi m}}{V}_1=0.3m/s{V}_2=?T_1=300K{T}_2=1200K\therefore \frac{V_1}{V_2}=\sqrt{\frac{8R{T}_1}{\pi M}\times \frac{\pi M}{8R{T}_2}}\Rightarrow \frac{0.3}{V_2}=\sqrt{\frac{300}{1200}}\Rightarrow V_2=0.6m/s$.