Question

The average velocity of an ideal gas molecule at ${27}^{o}C$ is $0.3m/sec$. The average velocity at ${927}^{o}C$ will be:

• A. $0.6m/sec$
• B. $0.3m/sec$
• C. $0.9m/sec$
• D. $3.0m/sec$

Answer 1

The correct option is A $0.6m/sec$

The expression for average velocity is:

$\sqrt{\frac{8RT}{\pi M}}$

$\sqrt{\frac{T1}{T2}}$ = $\sqrt{\frac{300}{1200}}$ =1/2

($927^{\circ }$) =2 x ($27^{\circ }$) =0.6$m{s}^{-1}$ is the answer.