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Question

The average velocity of an ideal gas molecule at 27° celsius is 0.3 metre per second the average velocity at 927 degree Celsius will be
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Solution

27°C = 300 K
927°C = 1200 K

Average velocity ∝ sqrt(Absolute Temperature)

v1 / v2 = sqrt(T1 / T2)
0.3 / v = sqrt(300 / 1200)
0.3 / v = 1 / 2
v = 0.6 m/s

Average velocity at 927°C is 0.6 m/s

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