The average velocity of an ideal gas molecule at 27° celsius is 0.3 metre per second the average velocity at 927 degree Celsius will be please give explanation with answer
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Solution
27°C = 300 K 927°C = 1200 K
Average velocity ∝ sqrt(Absolute Temperature)
v1 / v2 = sqrt(T1 / T2) 0.3 / v = sqrt(300 / 1200) 0.3 / v = 1 / 2 v = 0.6 m/s