The average weight of three men A , B, and C is 84 kg. D joins them and the average weight of the four becomes 80 kg. If E whose weight is 3 kg more than that of D replaces A, the averages weight of B, C , D and E becomes 79 kg. The weight of A is

65 kg

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70 kg

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75 kg

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80 kg

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Solution

The correct option is A 75 kg
Total weight of A + B + C = 84 x 3 = 252 kg
Total weight of A + B + C + D = 80 x 4 = 320 kg
$∴$ Weight of D = 320 - 252 = 68 kg
Given, E = D + 3 = (68 + 3) kg = 71 kg
Total weight of B + C + D + E = (79 x 4) kg = 316 kg
$∴$ Weight of B + C = 316 kg - 71 kg - 68 kg = 177 kg
Weight of A only = 320 kg - 177 kg - 68 kg = 75 kg

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Similar questions

Q. The average weight of three men

A, B

and

C

84

k g . D

joins them and the average weight of the four becomes

80

k g . E,

whose weight is

3 k g

more than that of

D,

replaces

A .

Now the average weight of

B, C, D

and

E

becomes

79

k g,

then the weight of

A

The average weight of 3 men A, B and C is 84 kg. Another man D joins the group and the average now becomes 80 kg. If another man E, whose weight is 3 kg more than that of D, replaces A, then the average weight of B, C, D and E becomes 79 kg. The weight of A is:

Q. The average weight of three men