The axis of the parabola 9 y 2-16 x -12 y -57-0 isA- 3 y-2 B- x-3 y-3C- y -3D- 2 x-3

The correct option is A 3y = 2 Since 9y^2 16x 12y 57=0 ⇒ ( y 2/3 )^2=16/9 ( x+61/16 ) Put y 2/3=Y and x+61/16=X ⇒ Y^2=4 ( 4/9 )X Axis of this parabola is Y ...

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Standard XII

Mathematics

Axis

The axis of t...

Question

The axis of the parabola $9 y^{2} - 16 x - 12 y - 57 - 0$ is

3y = 2

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x + 3y =3

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2x = 3

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y = 3

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Solution

The correct option is A
3y = 2

$S i n c e 9 y^{2} - 16 x - 12 y - 57 = 0 \Rightarrow {(y - \frac{2}{3})}^{2} = \frac{16}{9} (x + \frac{61}{16}) P u t y - \frac{2}{3} = Y a n d x + \frac{61}{16} = X \Rightarrow Y^{2} = 4 (\frac{4}{9}) X$

Axis of this parabola is $Y = 0 \Rightarrow y - \frac{2}{3} = 0 \Rightarrow 3 y = 2$

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Q. The axis of the parabola

9 y^{2} - 16 x - 12 y - 57 = 0

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9 y^{2} - 16 x - 12 y - 57 = 0

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9 y^{2} - 16 x - 12 y - 57 = 0

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9 y^{2} - 16 x - 12 y - 57 = 0

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9 y^{2} - 9 x - 12 y - 57 = 0

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The axis of the parabola 9y2−16x−12y−57−0 is

The correct option is A 3y = 2 Since 9y2−16x−12y−57=0⇒(y−23)2=169(x+6116)Put y−23=Y and x+6116=X⇒Y2=4(49)X Axis of this parabola is Y=0⇒y−23=0⇒3y=2

The axis of the parabola $9 y^{2} - 16 x - 12 y - 57 - 0$ is