The axis of the parabola $x^{2} - 4 x - y + 1 = 0$ is

y=-3

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x=-3

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x=2

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none of these

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Solution

The correct option is C x=2
Given,

$x^{2} - 4 x - y + 1 = 0$

$\Rightarrow y = x^{2} - 4 x + 1$

$\Rightarrow y = {(x - 2)}^{2} - 3$

$\Rightarrow y + 3 = {(x - 2)}^{2}$

$\Rightarrow 4 \cdot \frac{1}{4} (y - (- 3)) = {(x - 2)}^{2}$

$(h, k) = (2, - 3), p = \frac{1}{4}$

The axis of parabola

$x = 2$

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