Question

The azeotropic mixture of water ($b.p.={100}^{0}C$) and HCl ($b.p.={85}^{0}C$) boils at ${108.5}^{0}C$. When this mixture is distilled it is possible to obtain:

• A. pure $HCl$
• B. pure $water$
• C. pure $water$ as well as pure $HCl$
• D. neither $HCl$ nor $H_{2}O$ in their pure states

Answer 1

The correct option is D neither $HCl$ nor $H_{2}O$ in their pure states

It is the example of negative azeotrope where b.p of the azeotropic mixture is higher than either of its constituents. It is also called the maximum boiling mixture.
So when the mixture is distilled then we can't obtain $HCl$ & $H_{2}O$ in their pure states.

Hence, the correct option is $D$