Question

The azeotropic mixture of water (b.pt.${100}^{o}C$) and HCI (b.pt. ${85}^{o}C$) boils at ${108.5}^{o}C$. When this mixture is distilled, it is possible to obtain:

• A. pure HCI
• B. pure water
• C. pure water as well as HCl
• D. neither HCl nor $H_{2}O$ in their pure states

Answer 1

The correct option is D neither HCl nor $H_{2}O$ in their pure states

Mixture having boiling point more than the boiling point of liquid A and liquid B

This type of azeotrope is formed by mixture showing -ve deviation.

The azeotropic mixture is a constant boiling mixture, it is not possible to separate the components of an azeotropic mixture by boiling.

Option D is correct.