The correct option is C 16 outer electrons and is isoelectronic with CO_2 N _3^ ⇒ #160;N̅ ≡ N → N̅ Azide ion has 16 outer electrons ...

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S Block Elements

The azide ion...

Question

The azide ion has:

20

outer electrons and is isoelectronic with

B r_{2} O

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18

outer electrons and is isoelectronic with

N O_{2}^{-}

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16

outer electrons and is isoelectronic with

C O_{2}

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14

outer electrons and is isoelectronic with

H_{2} O_{2}

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Solution

The correct option is C $16$ outer electrons and is isoelectronic with $C O_{2}$
$N_{3}^{-} \Rightarrow ¯ N \equiv N \to ¯ N$
Azide ion has $16$ outer electrons ( $5$ valence electrons from each nitrogen atom $+ 1$ for negative charge).
Total number of electrons are $22$ ( $7$ from each nitrogen atom $+ 1$ for negative charge). Total number of electrons in $C O_{2}$ are $22$ ( $6$ from carbon and $8$ each from oxygen atom).

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