Question

The azimuthal quantum number and the principal quantum number of the 17th electron are:

• A. l = 1, n = 3
• B. l = 3, n = 2
• C. l = 1, n = 17
• D. l = 2, n = 1

Answer 1

The correct option is A l = 1, n = 3

For an atom with 17 electrons, the configuration is, $1s^{2}2s^2{p}^{6}3s^2{p}^5$. Therefore the 17th electron is in p orbital with $n=3$ and $l=1$.