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Question

The b.p. of a solution of 5g of sulphur in 100g of carbon disulphide is 0.476o above that of pure solvent. Determine the moles of sulphur in this solvent. The b.p. of pure carbon disulphide is 46.30oC and its heat of vaporation is 84.1 calories per gram.

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Solution

ΔTb=0.4760CKb=2.4kg/molM=32nM=5×100032n×100ΔTb=Kb/m0.476=2.4/5×100032n×100=2432×5=154nn=154×0.476=151.9=8

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