The bag of sand of mass 2 kg is suspended by a rope. A bullet of mass 10 g is fired at it and gets embedded into it. The bag rises up a vertical height of 10 cm. The initial velocity of the bullet is nearly:
A
70 m/s
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B
140 m/s
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C
210 m/s
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D
281 m/s
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Solution
The correct option is D 281 m/s Mass of system M=2+0.01=2.01 Kg
Let the velocity after bullet embedded into sand bag be v
Mv22=Mgh⇒v=√2gh=√2×9.8×0.1=1.4m/s,
h=10cmor0.1m
Lets say the velocity of bullet be V
Then by momentum conservation mV=Mv⇒0.01×V=2.01×1.4