The balance equation for reaction of ethyl alcohol with Na is :
$C_{2} H_{5} O H + N a \to C_{2} H_{5} O N a + 1 / 2 H_{2}$

True

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False

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Solution

The correct option is A True
Reaction:
$C_{2} H_{5} O H + N a \to C_{2} H_{5} O N a + 1 / 2 H_{2}$

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Similar questions

$A + {S O C l}_{2}$ $\to$ $B + {S O}_{2} + H C l$
$X + N a \to C + H_{2}$
$B + C \to (C_{2} H_{5})_{2} O + N a C l$

Then A and X respectively are

K_{2} C r_{2} O_{7}

$A + S O C l_{2} \to B + S O_{2} + H C l X + N a \to C + H_{2} B + C \to (C_{2} H_{5})_{2} O + N a C l$

Then A and X are respectively

N a + 1 / 2 H_{2} \to N a H

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