The balanced chemical equation for potassium reacting with water is:

K (s) + 2 H_{2} O(l) \to KOH(aq) + H_{2} (g)

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2 K (s) + H_{2} O(l) \to 2 KOH(aq) + H_{2} (g)

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K (s) + H_{2} O (l) \to KOH(aq) + H_{2} (g)

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2 K (s) + 2 H_{2} O (l) \to 2 KOH(aq) + H_{2} (g)

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Solution

The correct option is D $2 K (s) + 2 H_{2} O (l) \to 2 KOH(aq) + H_{2} (g)$
Potassium reacts with water to form potassium hydroxide along with hydrogen. The chemical equation for this reaction is given below:

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Similar questions

2 K (s) + 2 H_{2} O (l) \to 2 K O H (a q) + H_{2} (g)

3.0

K (s) + H_{2} O (l) + (a q) ⟶ K O H (a q) + \frac{1}{2} H_{2} (g); Δ H = - 48.0 k c a l

H_{2} (g) + \frac{1}{2} O_{2} (g) ⟶ H_{2} O (l); Δ H = - 68.4 k c a l

K O H (s) + (a q) ⟶ K O H (a q); Δ H = - 14.0 k c a l

K O H_{(a q)} + H_{3} P O_{4 (a q)} \to K_{3} P O_{4 (a q)} + H_{2} O_{(l)}

H_{2} O

$KOH(aq) + {HNO}_{3} (aq) \to H_{2} O(l) + {KNO}_{3} (aq)$

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