Question

The balanced equation for the reaction $N{O}_3^{-}+F{e}^{2+}+H^{+}\to NO+F{e}^{3+}+H_{2}O$ is:

• A. $N{O}_3^{-}+3F{e}^{2+}+4H^{+}\to NO+2F{e}^{3+}+2H_{2}O$
• B. $N{O}_3^{-}+3F{e}^{2+}+2H^{+}\to 2NO+2F{e}^{3+}+H_{2}OC.N{O}_3^{-}+3F{e}^{2+}+2H^{+}--->3NO+2F{e}^{3+}+H_{2}O$
• C. $N{O}_3^{-}+3F{e}^{2+}+4H^{+}\to NO+3F{e}^{3+}+2H_{2}O$
• D. None of the above

Answer 1

The correct option is C $N{O}_3^{-}+3F{e}^{2+}+4H^{+}\to NO+3F{e}^{3+}+2H_{2}O$

Brown Ring Test:
The balanced equation is: $N{O}_3^{-}+3F{e}^{2+}+4H^{+}\to NO+3F{e}^{3+}+2H_{2}O$
Hence option (c) is correct.