The balanced reaction for the preparation of ethane from sodium propionate, using decarboxylation reaction is:

C H_{3} C H_{2} C O O H + N a O H C a O - - \to C_{2} H_{6} + H C O_{3}

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C H_{3} C H_{2} C N a O + 2 N a O H C a O - - \to C_{2} H_{6} + N a_{2} C O_{3}

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C H_{3} C H_{2} C O O N a + N a O H C a O - - \to C_{2} H_{4} + N a_{2} C O_{3}

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C H_{3} C H_{2} C O O N a + N a O H C a O - - \to C_{2} H_{6} + N a_{2} C O_{3}

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Solution

The correct option is D $C H_{3} C H_{2} C O O N a + N a O H C a O - - \to C_{2} H_{6} + N a_{2} C O_{3}$
Decarboxylation of sodium propionate results in the formation of ethane. The reaction is as follows:
$C H_{3} C H_{2} C O O N a + N a O H C a O - - \to C_{2} H_{6} + N a_{2} C O_{3}$

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C H_{4}

C H_{3} C O O N a + N a O H C a O / Δ - --- \to C H_{4} + N a_{2} C O_{3}

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