Question

The base a right-angled triangle measures 48 cm and its hypotenuse measures 50 cm. Find the area of the triangle.

Answer 1

By using Pythagoras theorem,
$H^2=P^2+B^2$
${50}^2=P^2+{48}^2$
P= $\sqrt{(2500-2304)}$
P = $\sqrt{\left(196\right)}$
P = 14cm.
Area of triangle= 0.5 × Base × Perpendicular
= 0.5 × 48 × 14
=24 × 14
=336 $c{m}^2$