Question

The base and height of the triangle are in the ratio $3:2$ and its area is $108c{m}^2$. Find the product of its base and height in cm${}^2$.

Answer 1

let base of triangle $=b$

and height of triangle $=h$

So,

$Area=\frac{1}{2}\times base\times height$

$108=\frac{1}{2}\times bh$

$bh=216c{m}^2$

Thus product base and height is $216c{m}^2$