The base and the altitude of a triangle are $(4 x - 2 y)$ and $(2 x + 2 y)$ respectively. What is the area of the triangle?

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Solution

The correct option is B
$A r e a o f a t r i a n g l e = \frac{1}{2} \times b a s e \times a l t i t u d e$
$A r e a = \frac{1}{2} (4 x - 2 y) \times (2 x + 2 y) = (2 x - y) (2 x + 2 y)$
$= 4 x^{2} - 2 x y + 4 x y - 2 y^{2}$
$= 4 x^{2} + 2 x y - 2 y^{2}$

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