The base and the altitude of triangular metal disc are $66 c m$ and $28 c m$ respectively. Find area of triangular sheet

Open in App

Solution

The base of triangle $66 c m$
The height of triangle $28 c m$
The area of triangle is $\frac{1}{2} \times 66 \times 28 33 \times 28 = 924 c m^{2}$

Suggest Corrections

Similar questions

Q. The area of a triangular field is

1.5

hectares and altitude is

300

m, find the corresponding base.

Q. Find the area, in square metres, of the trapezium whose bases and altitudes are as under:
(i) bases = 12 dm and 20 dm, altitude = 10 dm
(ii) bases = 28 cm and 3 dm, altitude = 25 cm
(iii) bases = 8 m and 60 dm, altitude = 40 dm
(iv) bases = 150 cm and 30 dm, altitude = 9 dm.

The base of a triangular field is three times its altitude. If the cost of sowing seeds in the field at 58/- per hectare is 783/-,find base and altitude.

Q. Find the area of a triangle whose base and altitude are 5 cm and 4 cm respectively.

The altitude and the base of a triangular field are in the ratio 6 : 5. If its cost is Rs 49,57,200 at the rate of Rs 36,720 per hectare and 1 hectare =10,000 sq. m, find (in metre) dimensions of the field.

Area of the given triangular field $= \frac{C o s t o f t h e f i e l d}{R a t e} = \frac{49, 57, 200}{36, 720}$ hectare

=135 hectare

$= 135 \times 10, 000$ sq. m=1350000 $m^{2} .$

Join BYJU'S Learning Program

The base and the altitude of triangular metal disc are 66 cm and 28 cm respectively. Find area of triangular sheet

The base of triangle 66cmThe height of triangle 28cmThe area of triangle is 12×66×2833×28=924cm2

The base and the altitude of triangular metal disc are $66 c m$ and $28 c m$ respectively. Find area of triangular sheet

The base of triangle $66 c m$
The height of triangle $28 c m$
The area of triangle is $\frac{1}{2} \times 66 \times 28 33 \times 28 = 924 c m^{2}$