Question

The base and the height of a triangle are in the ratio 4 : 5. If the area of the triangle is 40 $m^2$; find its base and height.

Let base be 4x m and height be 5x m.

$\therefore \frac{1}{2}\times 4x\times 5x=40.$

Answer 1

Let base of $\Delta$ =4x m

and height of $\Delta$ =5x m

area of $\Delta =40m^2$

$\because \frac{1}{2}$ base $\times$ height =area of $\Delta$

$\frac{1}{2}\times 4x\times 5x=40$

$10x^2=40$

$x^2=4$

$x=\sqrt{4}$

x =2

$\therefore$ base $=4x=4\times 2=8m$

height $=5x=5\times 2=10m$

$\therefore$ 8 m; 10 m