The base and the height of a triangle are in the ratio $4 : 5.$ If the area of the triangle is $40 m^{2};$ find its base and height.

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Solution

The base and the height of a triangle are in the ratio $= 4 : 5$
So,
$B a s e = 4 x$
$H e i g h t = 5 x$
Since, area of the triangle $= 40 m^{2}$
$\frac{1}{2} \times 4 x \times 5 x = 40$
$20 x^{2} = 80$
$x^{2} = 4$
$x = 2$
Therefore,
$B a s e = 4 \times 2 = 8 m$
$H e i g h t = 5 \times 2 = 10 m$

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Similar questions

The base and the height of a triangle are in the ratio 4 : 5. If the area of the triangle is 40 $m^{2}$ ; find its base and height.

Let base be 4x m and height be 5x m.

$∴ \frac{1}{2} \times 4 x \times 5 x = 40.$

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