The base and the height of a triangle are in the ratio 4 : 5. If the area of the triangle is 40 m² ; find its base and height?

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Solution

Let base of ∆ = 4x m and height of ∆ = 5x m
area of ∆ =40 m²
Area of $△ = \frac{1}{2} \times b a s e \times h e i g h t$
$\frac{1}{2} \times 4 x \times 5 x = 40 10 x^{2} = 40 x^{2} = 4 x = 2$
Base = 4x
$4 \times 2 = 8 m$
Height = 5x
$5 \times 2 10 m .$

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4 : 5

40 m^{2}

The base and the height of a triangle are in the ratio 4 : 5. If the area of the triangle is 40 $m^{2}$ ; find its base and height.

Let base be 4x m and height be 5x m.

$∴ \frac{1}{2} \times 4 x \times 5 x = 40.$

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