The base and top radius of a cone is 14 m and 8 m respectively. The height of the cone is 123 m. What is the volume of frustum of a cone? (Use π = 3.14).
A
48,302.64 in
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
47,891.28 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
47,891.28 cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
47,891.28 m3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D 47,891.28 m3 Volume of the frustum cone V = πh3(R2+Rr+r2) R=14m,r=8m,h=123m V=(3.14×123)/(3)[142+14×8+82] =3.14×41[196+112+64] =128.74[372] =47,891.28m3