Radius of the base of the jug =5 in
Given that, base area of the jug = 25π in2
Value of π=227
⇒ Base area of the jug =227×25
=22×557
=5507=78.571428..≃78.6 (estimated to the nearest tenth)
So, the area of the base of the jug is 78.6 sq in.
So, option A is the correct answer.