The base edge of a square pyramid with slant height 24cm is 14cm. Then its lateral edge is:

22 cm

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32 cm

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25 cm

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30 cm

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Solution

The correct option is C
25 cm

The slant height of square pyramid= $\sqrt{(L a t e r a l e d g e)^{2} - (H a l f t h e b a s e e d g e)^{2}}$
Let the lateral edge be 'x' cm . Then,
$24 = \sqrt{x^{2} - 7^{2}}$
$576 = x^{2} - 7^{2}$
$⟹ x^{2} = 625$
$⟹ x = 25 cm$

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The base edge of a square pyramid with slant height 24cm is 14cm. Then its lateral edge is:

The correct option is C 25 cm The slant height of square pyramid= √(Lateral edge)2−(Half the base edge)2 Let the lateral edge be 'x' cm . Then, 24=√x2−72 576=x2−72 ⟹x2=625 ⟹x=25 cm

The correct option is C
25 cm

The slant height of square pyramid= $\sqrt{(L a t e r a l e d g e)^{2} - (H a l f t h e b a s e e d g e)^{2}}$
Let the lateral edge be 'x' cm . Then,
$24 = \sqrt{x^{2} - 7^{2}}$
$576 = x^{2} - 7^{2}$
$⟹ x^{2} = 625$
$⟹ x = 25 cm$