Question

The base of a cylindrical vessel is $300c{m}^2$. Water is poured into it up to a depth of $6cm$. What will be the thrust acting on the base?

(Take density of water ${\rho }_w=1000kg/m^3$ and $g=10m/s^2$)

• A. $8N$
• B. $15N$
• C. $18N$
• D. $20N$

Answer 1

The correct option is C $18N$

Given,

Height of the cylinder, $h=6cm=0.06m$,

Area of the base,$A=300c{m}^2=300\times {10}^{-4}{m}^2$

$A=0.03m^2$

Density of water, ${\rho }_w=1000kg/m^3$

Acceleration due to gravity, $g=10m/s^2$

Mass of the water filled, $m$

We know,

$Density=\frac{mass}{volume}$

$\rho =\frac{m}{v}$

$⟹m=\rho \times V$

$m={\rho }_w\times A\times h$

$m=1000\times 0.03\times 0.06$

$m=1.8kg$

Thrust is the force along a particular direction.

Thrust, $F=m\times g$

$F=1.89\times 10$

$F=18N$