Question

The base of a parallelogram is' b' units. If its height is 14 more than its base, find the area of the parallelogram.

• A. ($b^2$ - 14b) sq. units
• B. ($b^2$ + 14b) sq. units
• C. ($b^2$) sq.units
• D. (b +14) sq.units

Answer 1

The correct option is B ($b^2$ + 14b) sq. units

Area of a parallelogram of base'b' and height 'h' = $b\times h$ sq. units.
Given: Base of the parallelogram = 'b' units
Height is 14 more than its base,
$\Rightarrow$Height of the parallelogram = (b+14) units
$\therefore$ Area of the parallelogram = $b\times \left(b+14\right)$ sq. units.
Applying the distributive property,
$b\times \left(b+14\right)$ = ($b^2$ + 14 b) sq. units