The base of a pyramid is a rectangle 40 m long and 20 m wide. The slant height of the pyramid from the midpoint of the shorter side of the base to the apex is 29 m. What is the volume of the pyramid?

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Solution

Height of the pyramid $= \sqrt{{(29)}^{2} - {(\frac{40}{2})}^{2}} = \sqrt{841 - 400} = \sqrt{441}$
$h = 21 m$
Volume of pyramid $=$ area of base $\times \frac{h}{3} = 40 \times 20 \times \frac{21}{3} = 5600 m^{2}$

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The base of a pyramid is a rectangle 40 m long and 20 m wide. The slant height of the pyramid from the midpoint of the shorter side of the base to the apex is 29 m. What is the volume of the pyramid?

Height of the pyramid =√(29)2−(402)2=√841−400=√441 h=21mVolume of pyramid = area of base ×h3=40×20×213=5600m2

Height of the pyramid $= \sqrt{{(29)}^{2} - {(\frac{40}{2})}^{2}} = \sqrt{841 - 400} = \sqrt{441}$
$h = 21 m$
Volume of pyramid $=$ area of base $\times \frac{h}{3} = 40 \times 20 \times \frac{21}{3} = 5600 m^{2}$