The base of a pyramid is an n-sided regular polygon of area $360$ $c m^{2}$ . The total surface area of the pyramid is $900$ $c m^{2}$ . Each lateral face of the pyramid has an area of $30$ $c m^{2}$ . Find n.

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Solution

Total area of the lateral faces = $900 - 360 = 540$ $c m^{2}$

Number of lateral faces it has $\frac{540}{30} = 18$ .

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The base of a pyramid is an n-sided regular polygon of area 360 cm2. The total surface area of the pyramid is 900 cm2. Each lateral face of the pyramid has an area of 30 cm2. Find n.

Total area of the lateral faces = 900−360=540 cm2Number of lateral faces it has 54030=18.

The base of a pyramid is an n-sided regular polygon of area $360$ $c m^{2}$ . The total surface area of the pyramid is $900$ $c m^{2}$ . Each lateral face of the pyramid has an area of $30$ $c m^{2}$ . Find n.

Total area of the lateral faces = $900 - 360 = 540$ $c m^{2}$

Number of lateral faces it has $\frac{540}{30} = 18$ .