Question

The base of a right angled triangle is 8 m and its hypotenuse is 10 m. Then its area is

• A. $48m^2$
• B. $40m^2$
• C. $30m^2$
• D. $24m^2$

Answer 1

Answer: (D)

$24m^2$

Given that,

Base of right angle triangle =8m

Hypotenuse =10m

Now,

Perpendicular $=\sqrt{{10}^2-8^2}=6$ m

Hence, Area of triangle $=\frac{1}{2}\times$ base$\times$ height

$=\frac{1}{2}\times 8\times 6=24m^2$