Question

The base of a right angled triangle is 8 m and its hypotenuse is 10 m Then its area is

• A. 48 $m^2$
• B. 40 $m^2$
• C. 30 $m^2$
• D. 24 $m^2$

Answer 1

The correct option is D 24 $m^2$

Given the base of a right angled triangle is 8 m and its hypotenuse is 10 m

Then height =$\sqrt{(10{)}^2-(8{)}^2}=\sqrt{100-64}=\sqrt{36}=6$ cm

Then area of triangle =$\frac{1}{2}\times 8\times 6=24$ sq cm