Question

The base of a right-angled triangle measures 48 cm and its hypotenuse measures 50 cm. Find the area of the triangle.

Answer 1

base = 48 cm
hypotenuse= 50 cm .

By Pythagoras theorem, we get

$h^2=b^2+p^{2}So,p^2=h^2-b^2\Rightarrow p^2={50}^2-{48}^2\Rightarrow p^2=2500-2304\Rightarrow p^2=196\Rightarrow p=\sqrt{196}\Rightarrow p=14So,Perpendicular=14cm.Nowareaoftriangle=\frac{1}{2}\times base\times height=\frac{1}{2}\times 48\times 14=48\times 7=336c{m}^2$