Question

The base of a right-angled triangle measures $48cm$ and its hypotenuse measures $50cm$. Find the area of the triangle. (in $c{m}^2$)

Answer 1

height $=\sqrt{(Hypotenuse{)}^2-(base{)}^2}$

$=\sqrt{(50{)}^2-(48{)}^2}$

$=14$

$\therefore$ Area $=\frac{1}{2}\times base\times height$

$=\frac{1}{2}\times 48\times 14$

$=336c{m}^2$