The base of a right prism is an equilateral triangle of edge $12$ m. If the volume of the prism is $288 \sqrt{3} m^{3}$ , then its height is:

6

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Solution

The correct option is D $8$ m
Volume of prism $=$ Area of prism $\times$ Height
$288 \sqrt{3} = \frac{\sqrt{3}}{4} a^{2} \times h$
$288 \sqrt{3} = \frac{\sqrt{3}}{4} 144 \times h$
$h = 8$ cm

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The base of a right prism is an equilateral triangle of edge 12m. If the volume of the prism is 288√3m3, then its height is:

The correct option is D 8mVolume of prism = Area of prism × Height288√3=√34a2×h288√3=√34144×hh=8 cm

The base of a right prism is an equilateral triangle of edge $12$ m. If the volume of the prism is $288 \sqrt{3} m^{3}$ , then its height is:

The correct option is D $8$ m
Volume of prism $=$ Area of prism $\times$ Height
$288 \sqrt{3} = \frac{\sqrt{3}}{4} a^{2} \times h$
$288 \sqrt{3} = \frac{\sqrt{3}}{4} 144 \times h$
$h = 8$ cm