The base of a triangle is $15 c m$ and area of the triangle is $87 s q . c m$ Find the height of the triangle.

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Solution

Given: Base of the triangle $= 15$ cm
Area of the triangle $= \frac{1}{2} \times$ base $\times$ height
$\Rightarrow 87 = \frac{1}{2} \times 15 \times$ height
$\Rightarrow$ height $= \frac{87 \times 2}{15} = 11.6 ‬$ cm
$∴$ height of the triangle is $11.6$ cm

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The base of a triangle is 15 cm and area of the triangle is 87 sq.cm Find the height of the triangle.

Given: Base of the triangle=15cmArea of the triangle=12× base× height⇒87=12×15× height⇒ height=87×215=11.6‬cm∴ height of the triangle is 11.6cm

The base of a triangle is $15 c m$ and area of the triangle is $87 s q . c m$ Find the height of the triangle.

Given: Base of the triangle $= 15$ cm
Area of the triangle $= \frac{1}{2} \times$ base $\times$ height
$\Rightarrow 87 = \frac{1}{2} \times 15 \times$ height
$\Rightarrow$ height $= \frac{87 \times 2}{15} = 11.6 ‬$ cm
$∴$ height of the triangle is $11.6$ cm