The base of an isoceles triangle cm- The perimeter is 62-15- What is the length of either of the remaining equal sides-

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Standard VIII

Mathematics

Applications (Word Problem)

The base of a...

Question

The base of an isoceles triangle is $\frac{4}{3}$ cm. The perimeter is $\frac{62}{15}$ . What is the length of either of the remaining equal sides?

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Solution

Perimeter = Sum of the length of all side = $\frac{4}{3} + x + x$ [as it is isosceles triangle, therefore the other two sides will be equal]
$\frac{62}{15} = \frac{4}{3} + 2 x x = \frac{21}{15}$

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The base of an isoceles triangle is 43 cm. The perimeter is 6215. What is the length of either of the remaining equal sides?

Perimeter = Sum of the length of all side = 43+x+x [as it is isosceles triangle, therefore the other two sides will be equal] 6215=43+2xx=2115

The base of an isoceles triangle is $\frac{4}{3}$ cm. The perimeter is $\frac{62}{15}$ . What is the length of either of the remaining equal sides?

Perimeter = Sum of the length of all side = $\frac{4}{3} + x + x$ [as it is isosceles triangle, therefore the other two sides will be equal]
$\frac{62}{15} = \frac{4}{3} + 2 x x = \frac{21}{15}$