Question

The base of an isosceles triangle is $3cm$ longer than each of the other sides. If the perimeter is $54cm,$ find the lengths of the sides.

Answer 1

Let the side of an isosceles triangle be $x$ cm since opposite sides of an isosceles triangle are equal. So another side $=xcm$

As given the base side is $3cm$ more then the other side.

So base side $=x+3cm$

$\Rightarrow$ Perimeter of a triangle $=$ sum of all sides

$\Rightarrow 54=x+x+x+3$

$54=3x+3$

$54-3=3x$

$51=3x$

$x=\frac{51}{3}$

$\Rightarrow x=17$

So the sides of triangle are $17cm$ and the base side of triangle $20cm.$

Hence, solved.